2x^2+46x-100=0

Solution for 2x^2+46x-100=0 equation:

2x^2+46x-100=0

a = 2; b = 46; c = -100;
Δ = b2-4ac
Δ = 462-4·2·(-100)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-54}{2*2}=\frac{-100}{4}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+54}{2*2}=\frac{8}{4}
=2
$